NEET2008PhysicsNuclear PhysicsActual
If M(A, Z), M_P and M_n denote the masses of the nucleus _Z^A X , proton and neutron respectively in units of u (1 u =931.5 MeV / c^2 ) and BE represents its binding energy in MeV , then
Options
- AM(A, Z)=Z M_p+(A-Z) M_n- BE / c^2
- BM(A, Z)=Z M_p+(A-Z) M_n+ BE
- CM(A, Z)=Z M_p+(A-Z) M_n-B E
- DM(A, Z)=Z M_p^P+(A-Z) M_n^n+B E / c^2
Correct answer
A. M(A, Z)=Z M_p+(A-Z) M_n- BE / c^2
Step-by-step solution
Binding energy of a nucleus containing N neutrons and Z protons is aligned & BE = [N M_n+Z M_p-M(A, Z) ] c^2 & BE c^2 =N M_n+Z M_p-M(A, Z) & BE c^2 =(A-Z) M_n+Z M_p-M(A, Z) & M(A, Z)=Z M_p+(A-Z) M_n- BE / c^2 aligned