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NEET 2006

Exam: NEET
Year: 2006
Subject: Physics
Chapter: Nuclear Physics

NEET 2006 · Physics · Nuclear Physics

The binding energy of deuteron is 2.2 MeV and that of _2^4 He is 28...

The binding energy of deuteron is 2.2

\mathrm{MeV}

and that of

{ }_2^4 \mathrm{He}

is

28 \mathrm{MeV}

. If two deuterons are fused to form one

{ }_2^4 \mathrm{He}

then the energy released is:

Options

A $30.2 \mathrm{MeV}$
B $25.8 \mathrm{MeV}$
C $23.6 \mathrm{MeV}$
D $19.2 \mathrm{MeV}$

Correct answer

C. $23.6 \mathrm{MeV}$

Step-by-step solution

Energy released

=28-2 \times 2.2 =28-4.1 =23.6 \mathrm{MeV}

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