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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Nuclear Physics

NEET 2005 · Physics · Nuclear Physics

In the reaction _1^2 H+ _1^3 H arrow _2^4 He+ _0^1 n , if the...

In the reaction 12H+13H→24He+01n{ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_0^1 n, if the binding energies of 12H,13H{ }_1^2 \mathrm{H},{ }_1^3 \mathrm{H} and 24He{ }_2^4 \mathrm{He} are respectively a,ba, b and cc (in Me V), then the energy (in MeV\mathrm{MeV} ) released in this reaction is:

Options

  1. Aa+b+ca+b+c
  2. Ba+b−ca+b-c
  3. Cc−a−bc-a-b
  4. Dc+a−bc+a-b

Correct answer

C. c−a−bc-a-b

Step-by-step solution

Energy in given reaction =BE=B E of products −B.E-B . E. of reactants =C−(a+h)=C−a−b\begin{aligned} & =C-(a+h) \\ & =C-a-b \end{aligned}
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