Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete $30$ oscillations as $60$ s and hence calculates the length of the simple pendulum as :
(Take $\pi^2 = 9.8$ , and $g = 9.8$ m/s $^2$ )

Question

Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete

30

oscillations as

60

s and hence calculates the length of the simple pendulum as :
(Take

\pi^2 = 9.8

, and

g = 9.8

m/s

^2

)

Quantrex Academy · Accepted Answer

Correct answer: D. 1 m

Time period T = (60)/(30) = 2 s. The formula for the time period of a simple pendulum is T = 2π (L)/(g) . Squaring both sides, we get T^2 = 4π^2 (L)/(g) . Substituting the given values T = 2 s, π^2 = 9.8 , and g = 9.8 m/s ^2 : (2)^2 = 4 × 9.8 × (L)/(9.8) 4 = 4L L = 1 m. Answer: 1 m

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