NEET2019PhysicsOscillationsActual
The displacement of a particle executing simple harmonic motion is given by, y = A 0 + A s i n ω t + B c o s ω t . Then, the amplitude of its oscillation is given by
Options
- AA 0 + A 2 + B 2
- BA 2 + B 2
- CA 0 2 + A + B 2
- DA + B
Correct answer
B. A 2 + B 2
Step-by-step solution
y = A 0 + A sin ω t + B cos ω t = A 0 + A 2 + B 2 · A A 2 + B 2 sin ω t + B A 2 + B 2 cos ω t = A 0 + A 2 + B 2 sin ω t + φ Amplitude = A 2 + B 2