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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20  m   s - 2 at a distance of 5   m from mean position. The time period of oscillation is

Options

  1. A2 s
  2. Bπ s
  3. C2 π s
  4. D1 s

Correct answer

B. π s

Step-by-step solution

Acceleration in SHM is a = ω 2 x 20 = ω 2 5 ⇒ ω 2 = 4 ⇒ ω = 2 ⇒ 2 π T = 2 T = π s

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