A pendulum is hung from the roof of a sufficiently high building...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is

20 m {s}^{- 2}

at a distance of

5m

from mean position. The time period of oscillation is

Options

A $2s$
B $\pis$
C $2\pis$
D $1s$

Correct answer

B. $\pis$

Step-by-step solution

Acceleration in SHM is

\left|a\right| = {\omega}^{2}x

20 = {\omega}^{2}5 ⇒ {\omega}^{2} = 4 ⇒ \omega = 2 ⇒ \dfrac{2\pi}{T} = 2

T = \pis

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