The sum of kinetic energy and potential energy of a simple pendulum bob is 0.02 joule. The speed of the simple pendulum bob at equilibrium position is approximately : (Consider mass of the bob = 20 g)

Step-by-step solution

Total energy of the simple pendulum is given as E = 0.02 J. Mass of the bob, m = 20 g = 0.02 kg. At the equilibrium position, the potential energy is zero and the total energy is purely kinetic. E = 1 2 m v^2 0.02 = 1 2 0.02 v^2 v^2 = 2 v = 2 1.41 m/s. Answer: 1.41 m/s