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NEET2024PhysicsOscillationsActual

A particle executing simple harmonic motion with amplitude A has the same potential and kinetic energies at the displacement

Options

  1. A2 A
  2. BA 2
  3. CA 2
  4. DA 2

Correct answer

C. A 2

Step-by-step solution

Potential energy = 1 2 k x^2 Kinetic energy = 1 2 k A^2- 1 2 k x^2 According to given condition 1 2 k x^2= 1 2 k A^2- 1 2 k x^2k 2 x^2=k A^2x^2= A^2 2 x= A 2

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