NEET2016PhysicsRotational MotionActual
A light rod of length, l has two masses, m 1 and m 2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is
Options
- Am 1 m 2 m 1 + m 2 l 2
- Bm 1 + m 2 m 1 m 2 l 2
- Cm 1 + m 2 l 2
- Dm 1 m 2 l 2
Correct answer
A. m 1 m 2 m 1 + m 2 l 2
Step-by-step solution
x 1 = m 2 l m 1 + m 2 and x 2 = m 1 l m 1 + m 2 . I = m 1 x 1 2 + m 2 x 2 2 = m 1 m 2 m 1 + m 2 l 2 .