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NEET 2016
Exam
NEET
Year
2016
Subject
Physics
Chapter
Rotational Motion

NEET 2016 · Physics · Rotational Motion

A uniform circular disc of radius 50cm at rest is free to rotate...

A uniform circular disc of radius 50cm\text{50}\text{cm} at rest is free to rotate about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0rads−22.0rads^{- 2}. Its net acceleration in ms−2ms^{- 2} at the end of 2.0 s\text{2.0 s} is approximately:

Options

  1. A8.08.0
  2. B7.07.0
  3. C6.06.0
  4. D3.03.0

Correct answer

A. 8.08.0

Step-by-step solution

At the end of 2sec,w=w0+\alphat\text{2}\text{sec,}w = {w}_{0} + \alphat

w=0+2(2)=4rad/secw = 0 + 2\left(2\right) = 4\text{rad/sec}

Particle acceleration towards the center is =ac=rw2= {a}_{c} = rw^{2}

ac=12(4)2=8m/s2{a}_{c} = \dfrac{1}{2}{\left(4\right)}^{2} = 8{\text{m/s}}^{2}

Tangential acceleration at=α⋅R{a}_{t} = \alpha ⋅ \text{R}

=1m/s2= 1{\text{m/s}}^{2}

anet=ac2+at2{a}_{net} = \sqrt{{a}_c^{2} + {a}_t^{2}}

=82+12= \sqrt{{8}^{2} + {1}^{2}}

=65≈8= \sqrt{65} \approx 8 (approximately)
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