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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Rotational Motion

NEET 2013 · Physics · Rotational Motion

The discs are rotating about their axes, normal to the discs and...

The discs are rotating about their axes, normal to the discs and passing through the centres of the discs. Disc D1D_1 has 2 kg2 \mathrm{~kg} mass and 0.2 m0.2 \mathrm{~m} radius and initial angular velocity of 50rads−150 \mathrm{rad} \mathrm{s}^{-1}. Disc D2\mathrm{D}_2 has 4 kg4 \mathrm{~kg} mass, 0.1 m0.1 \mathrm{~m} radius and initial angular velocity of 200rads−1200 \mathrm{rad} \mathrm{s}^{-1}. The two discs are brought in contact face to face, with their axes of rotation coincident. The final angular velocity (in rad s−1s^{-1} ) of the system is:

Options

  1. A60
  2. B100
  3. C120
  4. D40

Correct answer

B. 100

Step-by-step solution

M.J. of D1\mathrm{D}_1 is I1=MR22=2(0.2)22=0.04 kg m2\mathrm{I}_1=\frac{\mathrm{MR}^2}{2}=\frac{2(0.2)^2}{2}=0.04 \mathrm{~kg} \mathrm{~m}^2 initial angular velocity of D1D_1 is ω1=50radS−1\omega_1=50 \mathrm{rad} \mathrm{S}^{-1} M.J of D2\mathrm{D}_2 is I2=4×(0.1)22=0.02 kgm2\mathrm{I}_2=\frac{4 \times(0.1)^2}{2}=0.02 \mathrm{~kg} m_2 initial angular velocity of D2\mathrm{D}_2 is ω2=\omega_2= 200 and S−1\mathrm{S}^{-1}. According to the law of conservation of angular moment \begin{gathered}L_1=L_2 \\ \therefore \mathrm{I}}_{1} \omega_1+ \mathrm{I}}_{2} \omega_2=\left(\mathrm{I}}_{1}+ \mathrm{I}}_{2}\right) \\ \Rightarrow \omega=\frac{l_1 w_1+l_2 w_2}{\mathrm{I}_1+1}\\ \therefore \omega=\frac{(0.04)^2 \times 50+(0.02)^2 \times 200}{0.04+0.02}\\ =\frac{2+4}{0.06}=100 \mathrm{rads}^{-1} \end{gathered}
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