A solid cylinder of mass 50kg and radius 0.5m is free to rotate...

In this question we have to calculate tension

Given M = 50 kg

R = 0.5 m

angular acceleration = 2 revolution/${s}^{2}$

Now, Balancing the Torque

\left(T\right) \times \left(R\right) = \left(\dfrac{M{R}^{2}}{2}\right)\left(\alpha\right)$<br /><img src="https://cdn-question-pool.Quantrex.app/pyq/neet/014b1337-58cf-41c3-bad6-c0fd065babe9-image.png" style="width: 206px; height: 300px;" /><br />$T = \left(\dfrac{MR}{2}\right)\left(\alpha\right) = \left(\dfrac{50 \times 0.5}{2}\right)\left(2 \times 2\pi\right) = 157N$

So, the tension will be 157 N