NEET2014PhysicsRotational MotionActual
A solid cylinder of mass 50   k g and radius 0.5   m is free to rotate about horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions s - 2
Options
- A25 N
- B50 N
- C78.5 N
- D157 N
Correct answer
D. 157 N
Step-by-step solution
In this question we have to calculate tension Given M = 50 kg R = 0.5 m angular acceleration = 2 revolution/ s 2 Now, Balancing the Torque T × R = M R 2 2 α T = M R 2 α = 50 × 0.5 2 2 × 2 π = 157   N So, the tension will be 157 N