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NEET 2006
Exam
NEET
Year
2006
Subject
Physics
Chapter
Rotational Motion

NEET 2006 · Physics · Rotational Motion

A uniform rod of length l and mass m is free to rotate in a...

A uniform rod of length ll and mass mm is free to rotate in a vertical plane about A\mathrm{A}. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (moment of inertia of the rod about A\mathrm{A} is ml23\frac{m l^2}{3} ). A uniform rod of length l and mass m is free to rotate in a vertical plane about A . The rod initially in horizontal

Options

  1. Amgl2m g \frac{l}{2}
  2. B3g2l\frac{3 g}{2 l}
  3. C2l3g\frac{2 l}{3 g}
  4. D3g2l2\frac{3 g}{2 l^2}

Correct answer

B. 3g2l\frac{3 g}{2 l}

Step-by-step solution

Here torque A uniform rod of length l and mass m is free to rotate in a vertical plane about A . The rod initially in horizontal
\tau=m g(12)\left(\frac{1}{2}\right)M. I. of rod⁡\operatorname{rod} about AA is: I=ml23∴\frac{m l^2}{3}\therefore Angular acceleration of the rod is α=τIα=mg(12)ml23=3g2l.\alpha=\frac{\tau}{I} \alpha=\frac{m g\left(\frac{1}{2}\right)}{\frac{m l^2}{3}}=\frac{3 g}{2 l} .
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