NEET2011PhysicsRotational MotionActual
The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2 t^3-6 t^2 The torque on the wheel becomes zero at
Options
- At=0.5 ~s
- Bt=0.25 ~s
- Ct=2 ~s
- Dt=1 ~s
Correct answer
D. t=1 ~s
Step-by-step solution
According to question, torque, =0 Its means that, =0 = d^2 d t^2 Given So (t)=2 t^3-6 t^2 aligned d d t & =6 t^2-12 t d^2 d t^2 & =12 t-12 ( = d^2 d t^2 =0 ) 12 t-12 & =0 t & =1 ~s aligned