Three particles, each of mass m gram, are situated at the vertices of an equilateral triangle ABC side l ~cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to A B and in the

Correct answer: C. (5)/(4) m l^2 According to the question aligned I_ A X & =m l²+m((l)/(2))^2 & =m l²+(5)/(4) & =(5)/(4)m l² aligned

NEET 2004

NEET 2004 · Physics · Rotational Motion

Three particles, each of mass m gram, are situated at the vertices...

Three particles, each of mass

m

gram, are situated at the vertices of an equilateral triangle

\mathrm{ABC}

side

l \mathrm{~cm}

(as shown in the figure). The moment of inertia of the system about a line

\mathrm{AX}

perpendicular to

A B

and in the plane of

A B C

, in gram

\mathrm{cm}^2

units will be: Three particles, each of mass m gram, are situated at the vertices of an equilateral triangle ABC side l ~cm (as shown

C. $\frac{5}{4} m l^2$

According to the question

\begin{aligned}I_{A X} & =m l²+m\left(\frac{l}{2}\right)^2 \\ & =m l²+\frac{5}{4}\\ & =\frac{5}{4}m l² \end{aligned}