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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Thermodynamics

NEET 2023 · Physics · Thermodynamics

A Carnot engine has an efficiency of 50 % when its source is at a...

A Carnot engine has an efficiency of 5050 % when its source is at a temperature 327°C.327 ° C . The temperature of the sink is:

Options

  1. A200°C200 ° C
  2. B27°C27 ° C
  3. C15°C15 ° C
  4. D100°C100 ° C

Correct answer

B. 27°C27 ° C

Step-by-step solution

Efficiency of Carnot engine is given by,

η=1−TsinkTsource⇒50100=1−Tsink(327+273)K⇒Tsink=12×600=300K=(300−273)°C=27°Cη = 1 - \dfrac{{T}_{sink}}{{T}_{source}} ⇒ \dfrac{50}{100} = 1 - \dfrac{{T}_{sink}}{\left(327 + 273\right)K} ⇒ {T}_{sink} = \dfrac{1}{2} \times 600 = 300K = \left(300 - 273\right) ° C = 27 ° C

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