NEET2023PhysicsThermodynamicsActual
A Carnot engine has an efficiency of 50 % when its source is at a temperature 327   ° C . The temperature of the sink is:
Options
- A200   ° C
- B27   ° C
- C15   ° C
- D100   ° C
Correct answer
B. 27   ° C
Step-by-step solution
Efficiency of Carnot engine is given by, η = 1 - T sin k T s o u r c e ⇒ 50 100 = 1 - T sin k 327 + 273   K ⇒ T sin k = 1 2 × 600 = 300   K = 300 - 273   ° C = 27   ° C