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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Thermodynamics

NEET 2023 · Physics · Thermodynamics

A container of volume 200 ~cm^3 contains 0.2 mole of hydrogen gas...

A container of volume 200 cm3200 \mathrm{~cm}^3 contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 K(R=8.3 J K−1 mol−1)200 \mathrm{~K}\left(R=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right) will be

Options

  1. A4.15×105 Pa4.15 \times 10^5 \mathrm{~Pa}
  2. B4.15×106 Pa4.15 \times 10^6 \mathrm{~Pa}
  3. C6.15×105 Pa6.15 \times 10^5 \mathrm{~Pa}
  4. D6.15×104 Pa6.15 \times 10^4 \mathrm{~Pa}

Correct answer

B. 4.15×106 Pa4.15 \times 10^6 \mathrm{~Pa}

Step-by-step solution

We know that PV=nRTP1=n1VRT\begin{aligned} & P V=n R T \\ & P_1=\frac{n_1}{V} R T\end{aligned}\begin{gathered}P_2=\frac{n_2}{V} R T \\ P_{\text{net }}=P_1+P_2\end{gathered} =(n1+n2)RTV=(0.2+0.3)×8.3×200200×10−6\begin{aligned} & =\left(n_1+n_2\right) \frac{R T}{V} \\ & =(0.2+0.3) \times \frac{8.3 \times 200}{200 \times 10^{-6}}\end{aligned} =8.3 \times 0.5 \times 10^6=4.15 \times 10^6 \mathrm{ Pa}$
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