A Carnot engine, having an efficiency of η = 1 10 as heat engine, is used as a refrigerator. If the work done on the system is 10   J , the amount of energy absorbed from the reservoir at a lower temperature is:

Step-by-step solution

For engine and refrigeration operating between two same temperature, the relationship between efficiency and coefficient of performance β , η = 1 1 + β 1 10 = 1 1 + β ⇒ β = 9 From the principle of the refrigerator, coefficient of performance is given by the ratio of the amount of energy absorbed from the reservoir to work, i.e., Q 2 W = β Q 2 10 = 9 Q 2 = 90   J .