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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Thermodynamics

NEET 2015 · Physics · Thermodynamics

Figure below shows two paths that may be taken by a gas to go from...

Figure below shows two paths that may be taken by a gas to go from a state A to a state C.
Figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:

Options

  1. A380 J
  2. B500 J
  3. C460 J
  4. D300 J

Correct answer

C. 460 J

Step-by-step solution

In cyclic process ABCA,

ΔUcyclic=0\Delta{U}_{cyclic} = 0

Qcyclic=W{Q}_{cyclic} = W

QAB+QBC+QCA={Q}_{AB} + {Q}_{BC} + {Q}_{CA} = Closed loop area

400+100+QCA=12×2×10−3×4×104400 + 100 + {Q}_{CA} = \dfrac{1}{2} \times 2 \times {10}^{- 3} \times 4 \times {10}^{4}

500−QAC=40500 - {Q}_{AC} = 40

QAC=460J{Q}_{AC} = 460J
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