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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Thermodynamics

NEET 2015 · Physics · Thermodynamics

One mole of an ideal diatomic gas undergoes a transition from A to...

One mole of an ideal diatomic gas undergoes a transition from AA to BB along a path ABAB as shown in the figure,

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure, The change

The change in internal energy of the gas during the transition is:

Options

  1. A20kJ20kJ
  2. B−20kJ- 20kJ
  3. C20J20J
  4. D−12kJ- 12kJ

Correct answer

B. −20kJ- 20kJ

Step-by-step solution

\DeltaU=nCv\DeltaT\DeltaU = n{C}_{v}\DeltaT

T=PVnRT = \dfrac{PV}{nR}

\DeltaT=P2V2−P1V2nR\DeltaT = \dfrac{{P}_{2}{V}_{2} - {P}_{1}{V}_{2}}{nR}

\DeltaU=nRγ−1(P2V2−P1V1nR)\DeltaU = \dfrac{nR}{\gamma - 1}\left(\dfrac{{P}_{2}{V}_{2} - {P}_{1}{V}_{1}}{nR}\right)

=P2V2−P1V1γ−1= \dfrac{{P}_{2}{V}_{2} - {P}_{1}{V}_{1}}{\gamma - 1}

=−8×10325=−20kJ= - \dfrac{8 \times {10}^{3}}{\dfrac{2}{5}} = - 20kJ
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