NEET2006PhysicsThermodynamicsActual
A Carnot engine whose sink is at 300 ~K has an efficiency of 40 % . By how much should the temperature of source be increased so as to increase its efficiency by 50 % of original efficiency?
Options
- A380 ~K
- B275 ~K
- C325 ~K
- D250 ~K
Correct answer
D. 250 ~K
Step-by-step solution
Efficiency of carnot engine = aligned & =1- T₂ T₁ & or T₂ T₁ =1- & =1- 40 100 = 3 5 & T₁= 50 100 n= 3 2 n & =500 ~K & array l New efficiency ^ = + 50 100 = 3 2 =60 % array & T₂ T₁ =1- 60 100 = 2 5 & T₁^ = 5 2 T₂= 5 2 300=750 . & aligned Increase in temperature of source aligned & =T₁^ -T₁ & =750-300=250 ~K . aligned