An ideal gas heat engine operates in a Carnot cycle between 227^ C and 127^ C . It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to:

Correct answer: D. 1.2 aligned & Efficiency of carnot engine =(W)/(Q_1) & =1-(T_2)/(T_1) & (W)/(6)=1-(400)/(500) & W=(6)/(5)=1.2 Kcal aligned

NEET 2003

NEET 2003 · Physics · Thermodynamics

An ideal gas heat engine operates in a Carnot cycle between 227^ C...

An ideal gas heat engine operates in a Carnot cycle between

227^{\circ} \mathrm{C}

and

127^{\circ} \mathrm{C}

. It absorbs

6 \mathrm{kcal}

at the higher temperature. The amount of heat (in kcal) converted into work is equal to:

D. 1.2

\begin{aligned}& \text{ Efficiency of carnot engine }=\frac{W}{Q_1}\\ & =1-\frac{T_2}{T_1}\\ & \frac{W}{6}=1-\frac{400}{500}\\ & \Rightarrow \quad W=\frac{6}{5}=1.2 \mathrm{Kcal} \end{aligned}