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NEET2004PhysicsThermodynamicsActual

One mole of an ideal gas at an initial temperature of T~ K does 6~ R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5 / 3 , the final temperature of gas will be:

Options

  1. A(T+2.4) K
  2. B(T-2.4) K
  3. C(T+4) K
  4. D(T-4) K

Correct answer

D. (T-4) K

Step-by-step solution

We know that work done in adiabatic process is: aligned & W= -1 V-1 (P_f V_f-P_i V_i ) & 6 R= -1 5 3 -1 (T_f-T_i ) & Since P V=R T & T_f-T_i=-4 & T_f=(T-4) K & aligned

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