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NEET2017PhysicsWaves and SoundActual

The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?

Options

  1. A10 Hz
  2. B20 Hz
  3. C30 Hz
  4. D40 Hz

Correct answer

B. 20 Hz

Step-by-step solution

Two successive frequencies of closed pipe n v 4 l = 220 ....(i) n + 2 v 4 l = 260 ......(ii) Dividing (ii) by (i), we get n + 2 n = 260 220 = 13 11 11 n + 22 = 13 n n = 11 So, 11 v 4 l = 220 v 4 l = 20 So fundamental frequency is 20 Hz.

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