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NEET 2017
Exam
NEET
Year
2017
Subject
Physics
Chapter
Waves and Sound

NEET 2017 · Physics · Waves and Sound

The two nearest harmonics of a tube closed at one end and open at...

The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?

Options

  1. A10 Hz
  2. B20 Hz
  3. C30 Hz
  4. D40 Hz

Correct answer

B. 20 Hz

Step-by-step solution

Two successive frequencies of closed pipe

nv4l=220\dfrac{nv}{4l} = 220 ....(i)

(n+2)v4l=260\dfrac{\left(n + 2\right)v}{4l} = 260 ......(ii)

Dividing (ii) by (i), we get

n+2n=260220=1311\dfrac{n + 2}{n} = \dfrac{260}{220} = \dfrac{13}{11}

11n+22=13n11n + 22 = 13n

n=11n = 11

So, 11v4l=22011\dfrac{v}{4l} = 220

v4l=20\dfrac{v}{4l} = 20

So fundamental frequency is 20 Hz.
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