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NEET2015PhysicsWaves and SoundActual

A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencier between these two. The lowest resonant frequency for this string is:

Options

  1. A205 Hz
  2. B10.5 Hz
  3. C105 Hz
  4. D155 Hz

Correct answer

C. 105 Hz

Step-by-step solution

Two consecutive resonant frequencies for a string fixed at both ends will be n v 2 l a n d n + 1 v 2 l ⇒ n + 1 v 2 l - n v 2 l = 420 - 315 v 2 l = 105 H z Which is the minimum resonant frequency.

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