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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Waves and Sound

NEET 2015 · Physics · Waves and Sound

The fundamental frequency of a closed organ pipe of length 20cm is...

The fundamental frequency of a closed organ pipe of length 20cm20cm is equal to the second overtone of an organ pipe open at both the ends. The length of the organ pipe open at both the ends is

Options

  1. A80cm80cm
  2. B100cm100cm
  3. C120cm120cm
  4. D140cm140cm

Correct answer

C. 120cm120cm

Step-by-step solution

For closed organ pipe, (n_c=\frac{V}{4 l}) For open organ pipe, (n_0=\frac{V}{2 l^{\prime}}) For the second overtone of an open organ pipe, n′=3n0=3V2l′′nc=n′V4l=3V2l′l′=6l=6×20l′=120 cm\begin{aligned} & n^{\prime}=3 n_0=\frac{3 V}{2 l^{\prime \prime}} \\ & n_c=n^{\prime} \\ & \frac{V}{4 l}=\frac{3 V}{2 l^{\prime}} \\ & l^{\prime}=6 l=6 \times 20 \\ & l^{\prime}=120 \mathrm{~cm} \end{aligned})$
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