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NTA Abhyas JEE Main2020ChemistryAldehydes and KetonesPractice

C H 3 2 C = C H C O C H 3 can be oxidized to C H 3 2 C = C H C O O H by

Options

  1. Achromic acid
  2. BNaOI, followed by acidification
  3. CCu at 573 K
  4. DK M n O 4 + H 2 S O 4

Correct answer

B. NaOI, followed by acidification

Step-by-step solution

C H 3 2 C = C H C O C H 3 is a methyl ketone and therefore, it can be easily oxidized to C H 3 2 C C H C O O H by haloform or iodoform reaction (NaOI). ( C H 3 ) 2 C = C H C O C H 3 → N a O I ( C H 3 ) 2 C = C H C O C I 3 → N a O H C H I 3 + ( C H 3 ) 2 C = C H C O O N a → ( C H 3 ) 2 C = C H C O O H Chromic acid and K M n O 4 , being strong oxidizing agents, will also attack the multiple bond and cause the cleavage giving the mixture of carboxylic acids.

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