NTA Abhyas JEE Main2020ChemistryAldehydes and KetonesPractice
In the reaction sequence C 6 H 5 CHO → Δ NH 2 OH / H ⊕ ( X ) → P 2 O 5 / Δ (Y) → H 2 O / H ⊕ (Z) (X), (Y) and (Z) respectively be
Options
- AC 6 H 5 C H = N - O H , C 6 H 5 C N , C 6 H 5 C O O H
- BC 6 H 5 C H = N O H , C 6 H 5 C O N H 2 , C 6 H 5 C O O H
- CC 6 H 5 - C H = N O H , C 6 H 5 C O O H , C 6 H 5 C O N H 2
- DC 6 H 5 - C H = N O H , C 6 H 5 C O O H , C 6 H 5 C N
Correct answer
A. C 6 H 5 C H = N - O H , C 6 H 5 C N , C 6 H 5 C O O H
Step-by-step solution
Here X is benzladehyde oxime, Y is cyanobenzene and Z is benzoic acid C 6 H 5 - C H O + N H 2 O H → C 6 H 5 - C H = N - O H ( X ) → P 2 O 5 / Δ C 6 H 5 - C ≡ N ( Y ) → H 3 O ⊕ / Δ C 6 H 5 - C O O H ( Z )