NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
For the reaction 2 H I ( g ) ⇌ H 2 ( g ) + I 2 ( g ) . The value of K c is 4. If 2 mol of H 2 , 2 mol of I 2 and 2 mol of HI are present in one litre container then moles of I 2 present at equilibrium is:
Options
- A0.8
- B3.2
- C2.4
- D4.4
Correct answer
C. 2.4
Step-by-step solution
k c = 4 = 2 + x 2 2 - 2 x 2 2 = 2 + x 2 - 2 x X = 0.4 Mol of I 2 at equilibrium = 2 + 0.4 = 2.4