NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
Equilibrium constant for the reaction 4 A ( g ) ⇌ B ( g ) + 2 C ( g ) is – Given: 2 A g ⇌ B g + Y g ; k c 1 = 8 C g ⇌ A g + 1 2 Y g ; k c 2 = 1 4
Options
- A32
- B16
- C2
- D128
Correct answer
D. 128
Step-by-step solution
2 A g ⇌ B g + Y g k c 1 = 8 ……. (1) 2 A g + Y g ⇌ 2 C g k c 2 = ( 4 ) 2 = 16 ……. (2) Add equation (1) and (2) 4 A g + Y g ⇌ B g + 2 C g k C = k c 1 × k c 2 = 8 × 16 = 128