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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

For the following three reactions I,II and III, equilibrium...

For the following three reactions I,II\text{I,}\text{II} and III,\text{III,} equilibrium constants are given
1. \text{CO}\left(\text{g}\right) + {H}_{2} \text{O}\left(\text{g}\right) ⇌ {\text{CO}_{2} \left(\text{g}\right) + {H}_{2} \left(\text{g}\right); {K}_{1}
2. {\text{CH}_{4} \left(\text{g}\right) + {H}_{2} \text{O}\left(\text{g}\right) ⇌ \text{CO}\left(\text{g}\right) + {\text{3H}_{2} \left(\text{g}\right); {K}_{2}
3. {\text{CH}_{4} \left(\text{g}\right) + \text{2}{H}_{2} \text{O}\left(\text{g}\right) ⇌ {\text{CO}_{2} \left(\text{g}\right) + \text{4}{H}_{2} \left(\text{g}\right); {K}_{3}
Which of the following relations is correct?

Options

  1. AK1K2=K3{K}_{1} \sqrt{{K}_{2}} \text{=}{K}_{3}
  2. BK2K3=K1{K}_{2} {K}_{3} \text{=}{K}_{1}
  3. CK3=K1K2{K}_{3} \text{=}{K}_{1} {K}_{2}
  4. DK3K23=K12{K}_{3} {K}_{2}^{3} \text{=}{K}_{1}^{2}

Correct answer

C. K3=K1K2{K}_{3} \text{=}{K}_{1} {K}_{2}

Step-by-step solution

As equation 3 is obtained on adding equation 1& and equation 2,\text{,} so K3=K1⋅K2.{K}_{3} \text{=}{K}_{1} ⋅ {K}_{2}.
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