NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
10 moles of A 2 , 15 moles of B 2 and 5 moles of A B are placed in a 2 litre vessel and allowed the come to equilibrium. The final concentration of A B is 10.5 M , A 2 g + B 2 g ⇌ 2 AB g Determine the value of equilibrium constant K C for the reaction.
Options
- A25.3
- B31.5
- C36.3
- D40.5
Correct answer
B. 31.5
Step-by-step solution
5 + 2 x 2 = 10.5 ; x = 8 K C = [ A B ] 2 A 2 B 2 = 5 + 2 x 2 2 10 - x 2 15 - x 2 = ( 21 ) 2 2 × 7 = 31.5