NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
The ionisation constant for N H 4 + in water is 5.0 × 1 0 - 10 at 25 o C .The rate constant for the reaction of N H 4 + and O H - to form N H 3 and H 2 O at 25 o C is 3.0 × 10 10   Lmol − 1 s − 1 . The rate constant for proton transfer from water to N H 3 is x × 1 0 5 . The value of 'x' is
Correct answer
6
Step-by-step solution
N H 4 + ⇌ N H 3 + H + K = 5 × 1 0 - 10 Now, H + + O H - ⇌ H 2 O K w = 1 0 14 now, K c   =   k f k b 5 × 10 4 = 3 × 10 10 k b k b = 6 × 10 5