Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice

Consider the following gaseous equilibria with equilibrium constants K 1 a n d K 2 respectively. S O 2 g + 1 2 O 2 ( g ) ⇌ S O 3 ( g ) 2 S O 3 g ⇌ 2 S O 2 g + O 2 ( g ) The equilibrium constants are related as

Options

  1. A2 K 1 = K 2 2
  2. BK 1 2 = 1 K 2
  3. CK 2 2 = 1 K 1
  4. DK 2 = 2 K 1 2

Correct answer

B. K 1 2 = 1 K 2

Step-by-step solution

For the reaction, S O 2 g + 1 2 O 2 ( g ) ⇌ S O 3 ( g ) Equilibrium constant, K 1 = [ S O 3 ] S O 2 O 2 1 / 2 ...(i) For the reaction, 2 S O 3 g ⇌ 2 S O 2 g + O 2 ( g ) Equilibrium constant, K 2 = S O 2 2 [ O 2 ] S O 3 2 ...(ii) On squaring both sides in Eq.(i), we get K 1 2 = S O 3 2 S O 2 2 [ O 2 ] ...(iii) Eq. (ii) × Eq (iii), we get K 1 2 × K 2 = 1 or K 2 = 1 K 1 2 or K 1 2 = 1 K 2

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in gaseous state 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ The value of K₃ for the 2026Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = 0.08 atm C (s) + CO ₂(g) 2 CO (g) K_ p₂ = 2 atm The partial pres 2026In a closed flask at 600 K, one mole of X₂ Y₄ (g) attains equilibrium as given below : X ₂ Y ₄(g) 2 XY ₂(g) At equilibrium, 75 % X₂ Y₄ (g) was dissociated and the total pressure is 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) B(g) . K_c for this reaction at 400 K is 4.0 . The pa 2026The reaction A(g) B(g) + C(g) was initiated with the amount ' a ' of A(g) . At equilibrium it is found that the amount of A(g) remaining is (a - x) at a total pressure of p . The e 2026The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) 1 T ( K ⁻¹) ₁₀ K_p 0.05 2026For the following reaction at 50° C and at 2 atm pressure, 2N₂O₅(g) 2N₂O₄(g)+O₂(g) N₂O₅ is 50 % dissociated. The magnitude of standard free energy change at this temperature is x . 2026At T(K) , the equilibrium constant of A₂(g) + B₂(g) C(g) is 2.7 10⁻⁵ . What is the equilibrium constant for 1 3 A₂(g) + 1 3 B₂(g) 1 3 C(g) at the same temperature? 2026 Full Chemical Equilibrium list All NTA Abhyas JEE Main PYQs