Plot of log (x/m) against log P is a straight line inclined at an angle 45 o . When the pressure is 0.5 atm and Freundich parameter k is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 = 0.699)

Step-by-step solution

log x/m = log k + 1/n log P 1/n = tan 45 o = 1; log k = log 10 = 1 x/m   =   kp 1 n   =   10* 0 .5 1   =   5 When m   =   1   g, x   =   5   g