Exam

NTA Abhyas

Year

2020

Subject

Chemistry

Chapter

Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

Initially, 0.8 mol of PC l _ 5 and 0.2 mol of PC l _ 3 are mixed in...

Initially, 0.8 mol of $PC{l}_{5}$ and 0.2 mol of $PC{l}_{3}$ are mixed in a one litre vessel. At equilibrium, 0.4 mol of $PC{l}_{3}$ is present. The value of ${K}_{c}$ for the reaction, $PC{l}_{5}$\left(g\right) ⇌ PC{l}_{3}$\left(g\right) + C{l}_{2}\left(g\right),$ would be

Step-by-step solution

So $x = 0.2$

${K}_{c} = \dfrac{\left[PC{l}_{3}\right]\left[C{l}_{2}\right]}{\left[PC{l}_{5}\right]} = \dfrac{0.4 \times 0.2}{0.6}$

= 0.13\text{mol}{\textL^{- 1}