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Initially, 0.8 mol of P C l 5 and 0.2 mol of P C l 3 are mixed in a one litre vessel. At equilibrium, 0.4 mol of P C l 3 is present. The value of K c for the reaction, P C l 5 g ⇌ P C l 3 g + C l 2 g , would be

Options

  1. A0.13 mol L - 1
  2. B0.66 mol L - 1
  3. C0.013 mol L - 1
  4. D0.05 mol L - 1

Correct answer

A. 0.13 mol L - 1

Step-by-step solution

So x = 0.2 K c = P C l 3 C l 2 P C l 5 = 0.4 × 0.2 0.6 = 0.13 mol L - 1

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