An equilibrium mixture in a vessel of capacity 100 litre contain 1mol N _ 2 ,2mol O _ 2 and 3molNO . Find number of moles of O _ 2 to be added, so that at new equilibrium the concentration of NO is 0.04mol/lit. .

Correct answer: A. (101)/(18) N _ 2 + O _ 2 ⇌ 2NO K = 3 ^ 2 2 × 1 …(i) N _ 2 _ 1 - z + O _ 2 _ 2 + y - z ⇌ 2NO _ 2z + 3 K = ( 3 + 2z ) ^ 2 ( 2 + y - z ) ( 1 - z ) …(ii) Given, 3 + 2z = 4 z = (1)/(2) (i) = (ii) y = (101)/(18)

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Chemistry
Chapter: Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

An equilibrium mixture in a vessel of capacity 100 litre contain...

An equilibrium mixture in a vessel of capacity

100 litre

contain

\text{1}\text{mol}{N}_{2},2\text{mol}{O}_{2}

and

\text{3}\text{mol}\text{NO}

. Find number of moles of

{O}_{2}

to be added, so that at new equilibrium the concentration of

\text{NO}

\text{0}\text{.04}\text{mol/lit}\text{.}

Options

A $\dfrac{101}{18}$
B $\dfrac{101}{9}$
C $\dfrac{202}{9}$
DNone of these

Correct answer

A. $\dfrac{101}{18}$

Step-by-step solution

{N}_{2} + {O}_{2} ⇌ 2NO

K = \dfrac{{3}^{2}}{2 \times 1}

…(i)

\mathop{{N}_{2}}_{1 - z} + \mathop{{O}_{2}}_{2 + y - z} ⇌ \mathop{2NO}_{2z + 3}

K = \dfrac{( 3 + 2z{)}^{2}}{( 2 + y - z ) ( 1 - z )}

…(ii)
Given,

3 + 2z = 4

z = \dfrac{1}{2}

(i) = (ii)

y = \dfrac{101}{18}

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