Ammonium carbonate dissociates as NH 2 COONH 4 (s) ⇌ 2NH 3 (g) + CO 2 (g) In a closed vessel having ammonium carbonate in equilibrium N H 3 is added such that partial pressure of N H 3 now to equals to the original total pressure. The ratio of total pressure now the original pressure is?

Step-by-step solution

NH 2 COONH 4 (s)   ⇌   2NH 3 (g)   +   CO 2 (g) Suppose P is pressure of C O 2 at equilibrium than P N H 3 = 2 P P T o t a l = 2 P + P = 3 P As K P = P N H 3 2 P C O 2 = 4 P 3 On adding N H 3 at equilibrium P N H 3 = P T o t a l = 3 P So K P = 4 P 3 = P N H 3 2 . P ' C O 2 4 P 3 = 3 P 2 P ' C O 2 P ' C O 2 = 4 9 P Now total P ' = 3 P + 4 9 P = 31 9 P Hence pressure ratio P ' P = 31 9 P 3 P = 31 27