For the following reaction A g a q + + C l a q - → A g C l s Given: Δ G f o , AgCl = - 112.44 kJ/mol; Δ G f o C l – = - 130 kJ/mol ; Δ G f o A g + = 75 kJ/mol Report your answer by rounding it upto nearest whole number. The K s p of AgCl is n × 1 0 - 10 .The value of 'n' is.

Step-by-step solution

A g a q + + C l a q - → A g C l s Δ G f o , AgCl = - 112.44 kJ/mol; Δ G f o C l – = - 130 kJ/mol ; Δ G f o A g + = 75 kJ/mol Δ G r e a c t i o n o = Δ G f o , AgCl- [ Δ G f o A g + + Δ G f o C l – ] = - 112.44 kJ-[75 kJ- 130 kJ] = -57.44 kJ -2.303RTlog K s p = Δ G r e a c t i o n o log ⁡ K s p = 57440 2.303 × 8.314 × 298 ≅ 10 K s p = 1 × 1 0 - 10 Hence n = 1