NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
Calculate the value of equilibrium constant of the reaction at 22 7 o C , if the Δ G o for the reaction X + Y ⇌ Z is - 4.606 kcal . ( R = 2.0 c a l . m o l - 1 K - 1 )
Options
- A100
- B10
- C2
- D0.01
Correct answer
A. 100
Step-by-step solution
Δ G o = - 2.303 R T log K - 4.606 = - 2.303 × 0.002 × 500 log K log K = 2 , K = 100 .