Exam

NTA Abhyas

Year

2020

Subject

Chemistry

Chapter

Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

When A _ 2 and B _ 2 are allowed to react, the equilibrium constant...

When ${A}_{2}$ and ${B}_{2}$ are allowed to react, the equilibrium constant of the reaction at $27 ° C$ is found $( {K}_{C} = 4 )$.
${A}_{2} ( g ) + {B}_{2} ( g ) ⇌ 2AB ( g )$
What will be the equilibrium concentration of AB?

Step-by-step solution

${K}_{C} = \dfrac{[ AB{]}^{2}}{[ {A}_{2} ] [ {B}_{2} ]}$
$4 = \dfrac{[ 2x / 4{]}^{2}}{\left(\dfrac{2 - x}{4}\right)\left(\dfrac{4 - x}{4}\right)}$
$4 = \dfrac{4x^{2}}{x^{2} - 6x + 8}$
$x^{2} - 6x + 8 = x^{2}$
$x = \dfrac{8}{6} = \dfrac{4}{3}$
\left(AB\right) = \dfrac{2x}{4} = \dfrac{2}{4} \times \dfrac{4}{3} = 0.66 .