For the equilibrium LiCl . 3N H _ 3 ( s ) ⇌ LiCl . N H _ 3 ( s ) +...

For the equilibrium

LiCl . 3N{H}_{3} ( s ) ⇌ LiCl . N{H}_{3} ( s ) + 2N{H}_{3} ( g ) ;

{K}_{P} = 9at{m}^{2}

at 310 K. A 5 L vessel contains 0.1 mole of

LiCl . N{H}_{3}

. How many mole of

N{H}_{3}

should be added to the flask at this temperature derive the backward reaction for completion? (use R = 0.082 atm-L/mol K)
[Report your answer upto two decimal places.] For the equilibrium LiCl . 3N H _ 3 ( s ) ⇌ LiCl . N H _ 3 ( s ) + 2N H _ 3 ( g ) ; K _ P = 9at m ^ 2 at 310 K. A 5 L

For the equilibrium LiCl . 3N H _ 3 ( s ) ⇌ LiCl . N H _ 3 ( s ) + 2N H _ 3 ( g ) ; K _ P = 9at m ^ 2 at 310 K. A 5 L

Correct answer

0.79

Step-by-step solution

{K}_{P} = 9 = {P}_{N{H}_{3}}^{2}

{P}_{N{H}_{3}} = 3

PV = nRT

3 \times 5 = ( a - 0.2 ) 0.082 \times 310

a = 0.79

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