NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
Consider the following reactions in which all the reactants and the products are in gaseous state. 2PQ ⇌ P 2 + Q 2 ; K 1 = 3.6 × 1 0 5 PQ + 1 / 2 R 2 ⇌ PQR ; K 2 = 6 × 1 0 - 3 The value of K 3 for the equilibrium 1 / 2 P 2 + 1 / 2 Q 2 + 1 / 2 R 2 ⇌ PQR is
Options
- A3 × 1 0 3
- B6 × 1 0 3
- C1.0 × 1 0 - 5
- D5 × 1 0 - 3
Correct answer
C. 1.0 × 1 0 - 5
Step-by-step solution
Given , 2PQ ⇌ P 2 + Q 2 K 1 = P 2 Q 2 [ P Q ] 2 = 3.6 × 1 0 5 PQ + 1 / 2 R 2 ⇌ PQR ; K 2 = [ PQR ] PQ R 2 1 / 2 = 6 × 1 0 - 3 For the required equilibrium 1 / 2 P 2 + 1 / 2 Q 2 + 1 / 2 R 2 ⇌ PQR ; K 3 = [ PQR ] P 2 1 / 2 Q 2 1 / 2 R 2 1 / 2 K 3 = K 2 × 1 K 1 = 6 × 1 0 - 3 × 1 3.6 × 1 0 5 = 6 × 1 0 - 3 0.6 × 1 0 3 = 1 × 1 0 - 5