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Consider the following cell reaction 2 F e s + O 2 g + 4 H + a q → 2 F e 2 + a q + 2 H 2 O l If E c e l l = E c e l l o at 25 o C and F e 2 + = 10 - 3 M , P O 2 = 0.01 atm and p H = x Value of x is

Options

  1. A1
  2. B2
  3. C3
  4. D4

Correct answer

A. 1

Step-by-step solution

For E cell = E cell o log Q must be zero Q = 1 Q = F e 2 + 2 H + 4 P O 2 ⇒ 1 0 - 6 ( 1 0 - 4 x ) 0.01 = 1 10 - 4 = 10 - 4 x x = 1

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