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Ag s + Fe 3 + aq ⟶ Ag + aq + Fe 2 + aq Given standard electrode potentials- E Fe 3 + / Fe 2 + o = + 0 . 7 7 V and E Ag + / Ag s o = + 0 . 8 0 V If the reaction is feasible, enter 1.00 as answer elsewise enter 0.00.

Correct answer

0.00

Step-by-step solution

Ag s + Fe 3 + aq ⟶ Ag + aq + Fe 2 + aq E cell o = E Fe 3 + / Fe 2 + o - E Ag + / Ag o = 0 . 7 7 - 0 . 8 0 = - 0 . 0 3 V The reaction is not feasible. Fe 2 + + Ag + ⟶ Ag s + Fe 3 + aq

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