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The resistance of 0 .01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm – 1 . The value of equivalent conductance of solution is-

Options

  1. A400 mho cm 2 g e q – 1
  2. B295 m h o c m 2 g e q – 1
  3. C419 m h o c m 2 g e q – 1
  4. D425 m h o c m 2 g e q – 1

Correct answer

A. 400 mho cm 2 g e q – 1

Step-by-step solution

Λ eq = k × 100 N = 1 R × l a × 1000 N = 1 R × cell constant × 1000 N = 1 220 × 0.88 × 1000 0.01 = 400 mho cm 2 g e q − 1

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