NTA Abhyas JEE Main2020ChemistryElectrochemistryPractice
EMF of the following cell is 0.6 volt. A g s A g B r s K B r 0.01 M | | A g N O 3 0.001 M | A g ( s ) K s p of A g B r is expressed as 1 × 10 - x , x is T a k e 2.303 R T F = 0.06 V
Correct answer
15.00
Step-by-step solution
A g → A g + L + e - A g + 0.001 M + e - → A g A g + ( 0.001 M ) → A g + ( L ) 0.6 = 0 - 0.06 1 l o g K s p 10 - 2 × 10 - 3 10 - 10 = K s p 10 - 5 ⇒ K s p = 10 - 15