NTA Abhyas JEE Main2020ChemistryElectrochemistryPractice
A current strength of 0.965 amperes is passed through excess fused A l C l 3 for 5 hours. How many litres of chlorine will be liberated at STP ? F = 96500 C
Options
- A2.016
- B1.008
- C11.2
- D20.16
Correct answer
D. 20.16
Step-by-step solution
1 F → 11.2 L Cl 2 at STP ∴ N o . o f F a r a d a y s = 9.65 × 5 × 60 × 60 96500 = 1.8 ∴ Volume of Cl 2 at STP = 1.8 × 11.2 L =   20 .16   L