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The resistance of conductivity cell containing 0 .001 M KCl solution at 298 K is 1500 Ω . What is the cell constant if conductivity of 0 .001 M KCl solution at 298 K is 0.146 × 1 0 - 3 S c m - 1 .

Options

  1. A0.200 c m - 1
  2. B0.219 c m - 1
  3. C0.195 c m - 1
  4. D0.190 c m - 1

Correct answer

B. 0.219 c m - 1

Step-by-step solution

Cell constant = c o n d u c t i v i t y c o n d u c tan ⁡ c e = Conductivity × Resistance = 0.146 × 1 0 - 3 S c m - 1 × 1500 Ω = 0.219 c m - 1

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