NTA Abhyas JEE Main2020ChemistryElectrochemistryPractice
The temperature coefficient of the emf i.e., dE dt = – 0.00065 VK – 1 for the cell C d | C d C l 2 1 M | | A g C l s | A g at 25 o C . Calculate the entropy changes ΔS 298 K for the cell reaction Cd + 2 AgCl → Cd 2 + + 2 Cl – + 2 Ag .
Options
- A– 105.5 J K – 1
- B– 150.2 J K – 1
- C– 75.7 J K – 1
- D– 125.5 J K – 1
Correct answer
D. – 125.5 J K – 1
Step-by-step solution
Δ S = + n F d E d t = 2 × 96500 × – 0.00065 = – 125.5   JK – 1